Question

For what value of k the following pair of equation have infinitely many solution ​

Answer 1

Answer:

k = 8

Step-by-step explanation:

For infinitely many solutions of the pair of linear equations

$\frac{a1}{a2} = \frac{b1}{b2} = \frac{c1}{c2} \\\\ \frac{2}{5} = \frac{k-2}{2k-1} = \frac{k}{2k-5} \\ \\Taking  \frac{2}{5} = \frac{k-2}{2k-1} \\\\ 2(2k-1) = 5(k-2)\\4k-2 = 5k-10\\5k-4k = 10-2\\k= 8$

Note; 2k-y will be (2k-1)y in your question.