Question

for what value of k the following pair of linear equation has unique solution kx + 3 Y is equals to 3 and 12 x + K Y is equal to 6​

Answer 1

Hope it will help you

Answer 2

Answer:

$k\neq \sqrt{15}$

Step-by-step explanation:

kx+3y-3 = 0

Compairing with ax+by+c = 0,

a₁ = k, b₁ = 3 & c₁ = -3

12x+ky-6 = 0

Compairing with ax+by+c = 0,

a₂ = 12, b₂ = k & c₂ = -6

Now, we that for a pair of linear equations to have unique solution:

$\frac{a_{1} }{a_{2} } \neq \frac{b_{1} }{b_{2} }$

Putting the values,

⇒$\frac{k}{12} \neq \frac{3}{k}$

⇒$k^{2} \neq 15$

⇒$k^{} \neq \sqrt{15}$

So, k is all the values except $\sqrt{15}$ for the pair of linear equations to have a unique solution