Question

For what value of k the following pair of linear
equation has unique solution?
kx + 3y =3
12x+ky=6
​

Answer 1

Step-by-step explanation:

Since the pair of equations has unique solution

→ k/12≠3/k

→ k ^2 ≠ 36

→k ≠ 6 or -6 .

Thus every value of k which is not equal to 6 or -6 will be the required value of k .

Answer 2

Hi dear ❤️

We know that for unique solution. (a1/a2) is not equal to (b1/b2). Then k/12 not equal to 3/k. K^2 is not equal to 36.

Then k is not equal to +6 or -6 . Yr answer is k= R-(6,-6) , where R is real no