Question

for what value of k the following pair of linear equations has infinitely many solutions 10x + 5y -(k-5)=0​

Answer 1

Answer : 10

Step-by-step explanation : 10x+5y−(k−5)=0and  

20x+10y−k=0

These given equations are in the form:

a  

1

​  

x+b  

1

​  

y+c  

1

​  

=0 and  

a  

2

​  

x+b  

2

​  

y+c  

2

​  

=0

Where

a  

1

​  

=10,b  

1

​  

=5 and c  

1

​  

=−(k−5)  

a  

2

​  

=20,b  

2

​  

=10 and c  

2

​  

=−k

System has infinitely many solutions.

20

10

​  

=  

10

5

​  

=  

−k

−(k−5)

​  

=  

k

k−5

​  

 

5k=10k−50

or k=10

The value of k is 10.

Pls mark me as the brainliest!