Question

for what value of k the following system of linear equation has no solution 3 X + Y = 1 2K - 1 X + K - 1 Y is equal to 2 + 1

Answer 1

Heya!

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Answer 2

HELLO........FRIEND!!

THE ANSWER IS HERE,

Given that equations,

=> 3x+y=1

=> 3x+y-1 =0........... (1)

=> (2k-1)x+(k-1)y=2+1

=> (2k-1)x+(k-1)y-3=0.......... (2)

We know that,

If two equations has no solutions.Then

$= > \: \frac{a1}{a2} = \frac{b1}{b2}$

=> 3/(2k-1) = 1/(k-1)

=> 3 (k-1) = 2k-1

=> 3k-3 = 2k-1

=> 3k-2k = -1+3

=> k = 2.


:-)Hope it helps u.