Math, asked by mohammedzeeshan44, 4 days ago

For what value of ‘k’ the given pair of linear equations are parallel : 2x+3y=5 , 4x+ky=8​

Answers

Answered by krishnaja221
0

Step-by-step explanation:

if k=6 this pair of equations does not have a solution.

therefore, the lines will be parallel.

Answered by Aryan0123
27

Answer :-

The value of k = 6

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Explanation :-

Consider 2 linear equations as:

  • a₁x + b₁y + c₁ = 0
  • a₂x + b₂y + c₂ = 0

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For lines to be parallel,

\sf{ \dfrac{a _{1}}{a_2} =  \dfrac{b_1}{b_2}  \neq \dfrac{c_1}{c_2}} \\  \\

In the given question,

  • a₁ = 2
  • a₂ = 4
  • b₁ = 3
  • b₂ = k

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a₁ ÷ a₂ = b₁ ÷ b₂

2 ÷ 4 = 3 ÷ k

⇒ 3/k = 1/2

⇒ k = 3 × 2

⇒ k = 6

k = 6

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KNOW MORE:

  • For lines to be coincident,

a₁/a₂ = b₁/b₂ = c₁/c₂

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