Question

for what value of k the given quadratic equation kx square - 6 x minus 1 is equal to zero has no real roots​

Answer 1

EXPLANATION.

Quadratic equation.

⇒ kx² - 6x - 1 = 0.

As we know that,

D = Discriminant  Or b² - 4ac = 0.

⇒ (-6)² - 4(k)(-1) = 0.

⇒ 36 + 4k = 0.

⇒ 4k = - 36.

⇒ k = -9.

                                                                                                                     

MORE INFORMATION.

Nature of the factors of the quadratic expression.

(1) = Real and different, if b² - 4ac > 0.

(2) = Rational and different, if b² - 4ac is a perfect square.

(3) = Real and equal, if b² - 4ac = 0.

(4) = If D < 0 Roots are imaginary and unequal or complex conjugate.

Answer 2

Answer:

• -9

Step-by-step explanation:

Given

• kx² - 6x - 1 = 0

To find

• Value of k

Solution

Discriminant = b² - 4ac = 0

↝ The discriminant of a quadratic equation tells us whether there are two solutions, one solution, or no solutions.

• (-6)² - 4(k)(-1) = 0
• + 36 + 4k = 0
• 36 = -4k
• k = -36/4
• k = -9

Hence, the value of k is -9.