Math, asked by JomiaThomas, 8 months ago

FOR WHAT VALUE OF K THE GIVEN QUADRATIC EQUATION WILL BE A COMPLETE SQUARE X2-2KX+3=0​

Answers

Answered by amitsnh
1

Answer:

x^2 - 2kx + 3= 0

x^2 - 2kx + k^2 - k^2 + 3 = 0

(x - k)^2 = k^2 - 3

clearly, the expression is a complete square but for the terms at RHS. Hence, if RHS is made zero, the expression will become complete square

k^2 - 3 = 0

k^2 = 3

k = +_√3

Answered by Anonymous
1

Step-by-step explanation:

The answer is (-3) I think

Similar questions