FOR WHAT VALUE OF K THE GIVEN QUADRATIC EQUATION WILL BE A COMPLETE SQUARE X2-2KX+3=0
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Answer:
x^2 - 2kx + 3= 0
x^2 - 2kx + k^2 - k^2 + 3 = 0
(x - k)^2 = k^2 - 3
clearly, the expression is a complete square but for the terms at RHS. Hence, if RHS is made zero, the expression will become complete square
k^2 - 3 = 0
k^2 = 3
k = +_√3
Answered by
1
Step-by-step explanation:
The answer is (-3) I think
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