Question

for what value of k, the linean equation x+ky=5 has x=3 and y=5 as solution​

Answer 1

Answer:

The given system of equations can be written as

x+2y−5=0

3x+ky−15=0

This system of equation is of the form

a

1

x+b

1

y+c

1

=0

a

2

x+b

2

y+c

2

=0

where, a

1

=1,b

1

=2,c

1

=−5 and a

2

=3,b

2

=k,c

2

=−15

The given system of equations will have a unique solution, if

3

1



=

k

2

⇒k



=6.

Answer 2

Answer:

2/5

Step-by-step explanation:

Substitute x=3 and y=5 in the equation, and find for k.

You get 3 + 5k = 5

=> 5k = 2

Therefore, k = 2/5.

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