Question

for what value of k the linear equation 2X+KY=8 has (2,1) as it's solution? if x=4 ,then find the value of y.​

Answer 1

Answer:

2x+ky=8

(2,1)is solution of it

2(2)+k(1)=8

4+k=8

k=8-4

k=4

2x+4y=8

x+2y=4

x=4

4+2y=4

2y=0

y=0

Answer 2

For k = 4 , the linear equation 2x + ky = 8 has (2, 1) as it's solution

y = 0 when x = 4

Solution:

Given that, the linear equation is:

$2x+ky = 8$

Given (2 , 1) is the solution

Substitute x = 2 and y = 1 in above equation

2(2) + k(1) = 8

4 + k = 8

k = 8 - 4

k = 4

Thus for k = 4 , the linear equation 2x + ky = 8 has (2, 1) as it's solution

If x = 4 ,then find the value of y ?

2x + ky = 8

Substitute x = 4 and k = 4

2(4) + 4(y) = 8

8 + 4y = 8

4y = 8 - 8

y = 0

Thus y = 0 when x = 4

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