Question

For what value of k, the linear pair of equations 2x-3y=1 and kx+5y=7 has a unique solution
please answer fast

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Answer 1

Answer:

hi

your answer is here !

Step-by-step explanation:

2x-3y-1=0 --(1)

kx+5y-7=0---(2)

compare (1) and (2) with a1xb1y+c1=0 and a2x+b2y+c2 =0

a1=2; b1=-3; c1=-1

a2=k; b2=5; c2=-7

given (1) and (2) has unique solution

therefore

a1/a2 ≠ b1/b2

2/k ≠-3/5

k/2≠-5/3

k≠-10/3

u can take k all real values other than -10/3

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