For what value of k, the numbers 3k+2,4k+3 and 6k-1 are in ap
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Answer:
k=5
Step-by-step explanation:
a=3k+2
b=4k+3
c=6k-1
2b=a+c
8k+6=3k+2+6k-1
-k=-5
k=5
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