For what value of k the pair of equation 2x+3y+5=0andkx +4y=10
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Given equations :-
» 2x + 3y + 5 = 0
» kx + 4y = 10
➡ kx + 4y - 10 = 0
we have to find the value of k such that the pair of equations have unique solution.
we know that, when pair of equations have unique solution,
a1/a2 ≠ b1/b2
➡ 2/k ≠ 3/5
just put any value of k so that it doesn't get equal to 3/5.
you can put 1, 2 etc.
for example, k is 2, then a1/a2 = 2/2 = 1
LHS ≠ RHS
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