Question

for what value of k the pair of equations x - 2y = 3, 3x + ky = 1 has a unique solution

Answer 1

Answer:

HOW TO SOLVE?

For unique solution,

$\frac{a1}{a2} \: is \: not \: equal \: to \: \frac{b1}{b2}.$

Now, it becomes

$\frac{ - 2}{k} = \frac{ - 3}{ - 1} \\ \frac{ - 2}{k} = 3 \\ k = \frac{ - 2}{3}$

The value of k must be -2/3 to become a pair of unique solution.

HAVE A NICE DAY!!!

HOPE IT HELPS YOU!!!