Question

for what value of k, the pair of linear equation 2x-y-3=0,2kx+7y-5=0 has a unique solution x=1,y=-1

Answer 1

GIVEN :

The pair of linear equation 2x-y-3=0,  2kx+7y-5=0 has a unique solution x=1, y=-1

TO FIND :

The value of k, the pair of linear equation 2x-y-3=0, 2kx+7y-5=0 has a unique solution x=1, y=-1

SOLUTION :

Given that  the pair of linear equations are 2x-y-3=0, 2kx+7y-5=0 has a unique solution x=1, y=-1

2x-y-3=0 --------- (1)

2kx+7y-5=0 --------- (2)

Since the given pair of equations have unique solution x=1 and y=-1, we have to substitute the values of x=1 and y=-1 in the 2nd equation to get the value of k.

2k(1)+7(-1)-5=0

2k-7-5=0

2k-12=0

2k=12

$k=\frac{12}{2}$

∴ k=6

∴ the value of k=6 makes the given pair of equations 2x-y-3=0, 2kx+7y-5=0 has a unique solution x=1 and y=-1.

Answer 2

Answer:

k=6

Step-by-step explanation:

k=6

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