for what value of k the pair of linear equation 2x-y-3=0,2kx+7y-5=0 has a unique solution
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Answered by
0
here is your answer by Sujeet,
For unique solution we must be have ,
a1/a2≠b1/b2
2/2k≠-1/7
2k≠14
k≠14/2
k≠7
that's all
For unique solution we must be have ,
a1/a2≠b1/b2
2/2k≠-1/7
2k≠14
k≠14/2
k≠7
that's all
Answered by
1
given pair of equations are
2x-y-3=0_____________________(1)
2kx+7y-5-0____________________(2)
for unique solution a1/a2 is not equal to b1/b2
2/2k is not equal to 1/7
14 is not equal to2k
k is not equal to 7
hence k may satisfy any value except 7
2x-y-3=0_____________________(1)
2kx+7y-5-0____________________(2)
for unique solution a1/a2 is not equal to b1/b2
2/2k is not equal to 1/7
14 is not equal to2k
k is not equal to 7
hence k may satisfy any value except 7
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