for what value of k the pair of linear equation 3 X + y is = 3 and 6 X + K y= 8 does not have a solution
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Answer:
Step-by-step explanation:
3x+y-3=0.................(1)
6x+ky-8=0..............(2)
here a1=3,b1=1,c1=3 in equation .....(1)
a2=6,b2=k,c2=8 in equation( 2)
now for the given pair to have a unique solution : a1/a2is not equal to b1/b2
i.e., 3/6is not equal to 1/k
i.e., k is not equal to 6
therefore , for all the value of k, except 6, the given pair of equations will have a unique solution
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