Question

for what value of k, the pair of linear equation 5x+y=3 and 10x+ky=8 does not have a solution

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Answer 1

Step-by-step explanation:

5x + y = 3. and. 10x + KY =8

5x + y - 3 = 0. 10 x + KY -8 =0

a1 = 5 , b1 = 1, c1 = -3. a2 = 10, b2 = K c2 = -8

a1/ a2 = 5/ 10 = 1/2

b1 / b2 = 1/ K

c1/ c2 = -3/ -8 = 3/8

a1/a2 = b1/b2 ≠ c1 / c2

have not solution

b1/b2 ≠ c1/ c2

1/k ≠ 3/8

8 ≠ 3K

K = 3/8