Question

For what value of k, the pair of linear equations 3x+y=3 and 6x+ky=8 does
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Answer 1

Answer:

The equation are

3x+5y−3=0 ....(1)

6x+ky−8=0 .....(2)

Here, a

1

=3,b

1

=5,c

1

=−3

and a

2

=6,b

2

=k,c

2

=−8

The given system has no solution if

a

2

a

1

=

b

2

b

1



=

c

2

c

1

⇒

6

3

=

k

5



=

−8

−3

⇒3k=30⇒k=10