Question

For what value of k, the pair of linear equations 3x+y=3

and 6x+ky=-8 does not have a solution.​

Answer 1

Answer:

k=2

Step-by-step explanation:

we know that if there is no solution then lines must be parallel and if lines are parallel than

$\frac{a1}{a2} = \frac{b1}{b2}$

≠ c1/c2

so,a1/a2=3/6= 1/2

b1/b2=1 / k

now

$\frac{1}{2 } = \frac{1}{k}$

so k=2