For what value of k, the pair of linear equations 3x+y=3 and 6x+ky=8 does
not have a solution.
Answers
Answered by
48
Answer:
2
Step-by-step explanation:
The case for no solution is:
a1/a2 = b1/b2 ≠ c1/c2
3x + y = 3
6x + ky = 8
3/6 = 1/k
1/2 = 1/k
k = 2
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