Math, asked by dev2455, 6 months ago

For what value of k, the pair of linear equations 3x+y=3 and 6x+ky=8 does

not have a solution.

Answers

Answered by studyhard2005
48

Answer:

2

Step-by-step explanation:

The case for no solution is:

a1/a2 = b1/b2 ≠ c1/c2

3x + y = 3

6x + ky = 8

3/6 = 1/k

1/2 = 1/k

k = 2

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