Question

For what value of k, the pair of linear equations 3x+y=3 and 6x+ky=8 does not

have a solution.​

Answer 1

Answer:

3x+y-3=0 .... eq i-

6x+ky-8=0 .... eq ii-

a1=3 , b1=1 , c1=(-3)

a2=6 , b2=k , c2=(-8)

If a1/a2 = b1/b2 ≠ c1/c2 has no solutions

3/6 = 1/k ≠ (-3)/(-8)

3/6 = 1/k

3k = 6 ....( cross multiplication )

k = 6/3

k = 2

Hope it's helpful...

Thanks.

Step-by-step explanation: