Math, asked by IqraBaig, 4 months ago

for what value of k the pair
of
linear
equations 3x+y=3 and
6 x + ky = 8 does not have
a solution .​

Answers

Answered by ankitsharma1997a
1

Answer:

3x + y = 3

6x +ky = 8

for no solution condition

a1/a2 = b1/b2 not equal to c1/c2

so 3/6 = 1/k

1/2 = 1/k

k = 2 ans

Answered by Shivali2708
1

3x+y =3

6x + ky = 8

therefore,

3/6 = 1/k is not equal to 3/8

3/6 = 1/k

thus k=2.

hope it helps..

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