for what value of k the pair
of
linear
equations 3x+y=3 and
6 x + ky = 8 does not have
a solution .
Answers
Answered by
1
Answer:
3x + y = 3
6x +ky = 8
for no solution condition
a1/a2 = b1/b2 not equal to c1/c2
so 3/6 = 1/k
1/2 = 1/k
k = 2 ans
Answered by
1
3x+y =3
6x + ky = 8
therefore,
3/6 = 1/k is not equal to 3/8
3/6 = 1/k
thus k=2.
hope it helps..
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