Question

For what value of k, the pair of linear equations kx - 4y = 3,6x - 12y =9 has an infinite number of solutions.

help me with this guysssss​

Answer 1

Answer:

2

Step-by-step explanation:

kx-4y-3=0

6x-12y-9=0

For infinite solutions,

a1/a2=b1/b2=c1/c2

k/6=4/12=3/9

k/6=4/12

k=2

k/6=3/9

k=3/9×6

k=2

Answer 2

Answer:

To get the value of k we must at least find a value of x and y.

Let, x = 1

then,

6x - 12y = 9

6(1) - 12y = 9

6 - 12y = 9

-12y = 9 -6

-12y = 3

y = 3/-12

y = 1/-4

So, if x = 1 then y = 1/-4

kx -4y =3

k(1) - 4(1/-4) =3

k + 1 = 3

k = 3 - 1

k = 2

Therefore k = 2 to get infinite number of solutions ❤️❤️❤️❤️❤️❤️