Question

For what value of k, the pair of linear equations kx-4y=3, 6x-12y=9 has an infinity number of solution​

Answer 1

Answer:

2

Step-by-step explanation:

Let, x = 1

then,

6x - 12y = 9

6(1) - 12y = 9

6 - 12y = 9

-12y = 9 -6

-12y = 3

y = 3/-12

y = 1/-4

%3D

So, if x = 1 then y = 1/-4

kx -4y =3

k(1) - 4(1/-4) =3

k+1

%3D

k

= 3 - 1

k

= 2

Therefore k= 2 to get infinite number of

solutions