For what value of k, the pair of linear equations kx –4y =3 and 6x -12y =9 has an infinite numbers of solutions.
Answers
Answered by
0
Answer:
hdhdeu uh vvyr4thhbhgfv7k
Answered by
0
Answer:
mark me brainlist
Step-by-step explanation:
We know that the system of equations
a
1
x+b
1
y=c
1
a
2
x+b
2
y=c
2
has no solution, if
a
2
a
1
=
b
2
b
1
=
c
2
c
1
Here, a
1
=3,b
1
=1,c
1
=1,a
2
=2k−1,b
2
=k−1,c
2
=2k+1
So, the given system of equations will have no solution, if
2k−1
3
=
k−1
1
=
2k+1
1
2k−1
3
=
k−1
1
and
k−1
1
=
2k+1
1
Now,
2k−1
3
=
k−1
1
⇒3k−3=2k−1⇒k=2
Clearly, for k=2 we have
k−1
1
=
2k+1
1
Hence, the given system of equations will have no solution, if k=2.
Similar questions