For what value of k, the points(k,-2),(1,4), and (-3,16) in given order are collinear ?
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Step-by-step explanation:
by slope formula ,
4+2/1-k==16-4/-3-1
6/1-k==12/-4
6/1-k== -3
-3+3k==6
3k==6+3
k==9/3
k==3
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