for what value of k the polynomial x³+4x²-kx+8 is exactly divisible by x-2
Answers
Answered by
6
Answer:
The value of k is 16
Step-by-step explanation:
If x³+4x²-kx+8 is exactly divisible by x-2, then when the value of x is substituted in the equation, the result must be zero.
x-2=0
x=2
x³+4x²-kx+8
(2*2*2) + (4*2*2) - (2*k) + 8 = 0
8 + 16 - 2k + 8 = 0
32 = 2k
k = 32/2 = 16
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Answered by
11
Answer:
Let the function be represented by f(x).
As x−2, exactly divides f(x), 2 is the zero of f(x)
Hence, f(2)=0.
f(x)=x
3
+4x
2
−px+8
⇒f(2)=2
3
+4×2
2
−p×2+8=0
⇒2p=32
⇒p=16
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