Question

for what value of k the quadratic equation 2kx squre -40x+25=0 has equal roots also find the roots

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Answer 1

Step-by-step explanation:

$for \\ a {x}^{2} + bx + c = 0 \\ \\ to \: have \: equal \: roots \\ \\ {b}^{2} - 4ac = 0 \\ \\ here \\ \\ a = 2k \\ \\ b = - 40 \\ \\ c = 25 \\ \\ {( - 40)}^{2} - 4(2k)(25) = 0 \\ \\ 200k = 1600 \\ \\ k = 8 \\ \\The \:roots\:are\:-\frac {b}{2a}\\\\frac {40}{16}=\frac {5}{2}$

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