Question

for what value of k the quadratic equation kx(x-1)+1=0 has equal roots?

Answer 1

ANSWER:-

Here,kx(x-1)+1=0

kx^2-kx+1=0

for equal roots,b^2-4ac

(-k)^2-4(k)(1)

k^2-4k=0

k(k-4)

So,k=4

HOPE IT HELPS YOU

Answer 2

Answer:

Step-by-step explanation

K =3