For what value of k, the quadratic equation kx2 – 4x + 3 = 0, has no real roots?
Answers
Answered by
3
Answer:
Explanation:
For one real root ( or equal roots) then the discriminant
Δ
=
b
2
−
4
a
c
=
0
k
x
2
−
4
x
−
3
=
0
Δ
=
(
−
4
)
2
−
4
×
k
×
(
−
3
)
=
0
16
+
12
k
=
0
k
=
−
16
12
=
−
4
3
If this is correct then the resulting quadratic can be factorised as a perfect square.
−
4
3
x
2
−
4
x
−
3
=
0
giving
4
x
2
+
12
x
+
9
=
0
factorising to:
(
2
x
+
3
)
2
=0
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Answered by
10
Step-by-step explanation:
kx²-4x+3=0
a=k,b= -4,c=3
∆=b²-4ac<0
=>(-4)²-4(k)(3)<0
=>16-12k<0
=>-12k<-16
=>k<4/3
=>k<1.33
k=1.32 or 1.31 or 1.3 ...
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