for what value of k the root of the quadratic equation K + 4 x square + K + 1 X + 1 is equal to zero are equal
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b²-4ac=0
(k+1)² -4(k+4)(1)=0
k²+1+2k-4k-16=0
k²-2k-15=0
k²-5k+3k-15=0
k(k-5)+3(k-5)=0
(k+3)(k-5)=0
k= -3 , 5
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I hope this will help you
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