Question

for what value of k' the roots of the eq: x²+42+k=0
are real ?​

Answer 1

Answer:

-91

Step-by-step explanation:

if k=-91

x^2+42+-91=0

x^2-49=0

x^2=49

x=$\sqrt{49}$

x=7

which is a real root

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Answer 2

Answer:

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Step-by-step explanation: