Question

For what value of k, the roots of the equation x^2+4x+k=0are real.
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Answer 1

Step-by-step explanation:

a=1, b=4, c=k

b^2-4ac=0 (Since the roots are real)

=> 4^2-4×1×k=0

=> 16-4k=0

=> 16=4k

=> k=4.