Question

For what value of k, the roots of the equation x + 4x + k = 0 are real ?
(a) ks 4
(b) k24
(c)k s 2​

Answer 1

Answer:

For the equation x^2+4x +k=0, to have real roots, discriminant should be greater than 0.

d=b^2-4ac

4^2-4×1×k > 0

16-4k > 0

k should be greater than 4.

All real values greater than 4 can be the value of k.

Answer 2

Step-by-step explanation:

so this is the solution