Math, asked by vidushitalwar44, 1 year ago

for what value of k the roots of the equation x2-(2k-1)x+k2=0 are real

Answers

Answered by khushalbit
2
for real roots b2-4ac>=0
there gore (2k-1)2 -4 *1*k2>=0
4k2 +1-8k -4k2>=0
-8k>=-1
8k<=1
k<=(1/8)

vidushitalwar44: thanks a lot
vidushitalwar44: It's 4k2+1-4k-4k2>=o
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