For what value of k the system of equation have unique solution X-KY=2 and 3 X + 2 y = -5
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Given:
x-ky=2 ........................(1)
3x+2y=-5....................?
3x+2+5=........,..............(2)
formet used:
=> a1x+b1y+c1=0
=>. a2x+b2y+c2=0
Unique Solution:
=> a1/a2 doesn't equal to b1/b2
To find:
a1= 1. b1=-k. c1= 2
a2=3. b2=2. c2= 5
•••> a1 /a2 doesn't equal to b1/b2 (given)
Now,
1/3 doesn't equal to -k/2
=>. k\ 2 doesn't equal to -1/3
=>. K doesn't equal to -2/3
Hence:
unique Solution of value system the find.
-k/3. -1/3. -k/3.
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