Question

For what value of K the system of equations 6x –2y = 3 and Kx -y = 2 has a unique solution?

Answer 1

Answer:

Given that,

6x-2y=3

kx-y=2

The condition for unique solution is,

a1/a2≠b1/b2

6/k≠2/1

k≠3

Step-by-step explanation:

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