for what value of k, the system of equations
kx + 4y -5 = 0 & 4x +8y -3 = 0 has no solution
Answers
Answered by
2
Step-by-step explanation:
a1 = k , b1 = 4 , c1 = -5
a2 =4 , b2 = 8 , c2 = -3
we know the equation have no solution when
a1/a2 = b1/b2 not equal to c1/c2
K/4 = 4/8
or , 8k = 16 ( by cross multiplication method )
or , k = 16/8
or , k = 2
Answered by
4
Given Equation
⇒kx + 4y - 5 = 0 (i)
⇒4x + 8y - 3 = 0 (ii)
To Find The value of k
Condition
⇒Given Equation has no Solution
So know that
⇒a₁/a₂ = b₁/b₂ ≠ c₁/c₂
We have
⇒a₁ = k , b₁ = 4 and c₁ = -5
⇒a₂ = 4 , b₂ = 8 and c₂ = -3
So put the value on
⇒a₁/a₂ = b₁/b₂
⇒k/4 = 4/8
⇒k/4 = 1/2
using Cross Multiplication , we get
⇒2k = 4
⇒k = 4/2
⇒k = 2
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