Math, asked by sunny22E, 1 year ago

For what value of k the system of equations kx-4y-8=0) and 8x-by+
skar-4y-8=0 and 8x-6y+2 = 0 has a unique
solution?​

Answers

Answered by Awesome98
5

Answer:

k=16

Step-by-step explanation:

For an equation to be Unique solution, we have a condition that is given below:

  • A1/A2≠B1/B2
  • k/8≠-4/-6
  • k/8≠4/6
  • 6k≠32
  • k≠32/6
  • k≠16/3

Therefore, Value of k will be 16/3.

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