Question

for what value of k the zeros of polynomial x²-5x+k differs by 1


clear explanation ​

Answer 1

Answer:

I WILL GIVE CLEAR ;) EXPLANATION....

SO JUST TAKE LET ZEROES BE A ND A+1

PUTTING A IN PLACE OF X IN EQ.

(A)²-5(A)+k=0

k = 5A - (A)²

Now putting x = A+1

(A+1)² -5A -5 + (5A -A²) =0

A² + 1 +2A -5A - 5 + 5A - A² =0

2A-4 = 0

A = 4/2 = 2

Hence zeroes are 2 and 3 of eq.

and value of k = 5A - A² = 10 -4 = 6 or 15-9 = 6

hence when k = 6 two zeroes be obtain with difference of 1.

Step-by-step explanation:

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