Question

for what value of k well the consecutive terms took 2k+ 1, 3 k + 3 and 5 k - 1 form in AP

Answer 1

in AP
3k+3-2k-1= 5k-1-3k-3
=k+2=2k-4
=k-2k=-4-2
-k=-6
=k=6

Answer 2

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