for what value of k will 3 X + 2 Y = 1, (2k+1)x +( k+2)y=k-1 have infinite number of solution
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Answered by
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a1/ a2 = b1/ b2
3 / (2k + 1) = 2 / (k + 2)
3k + 6 = 4k +2
k = 4. ANSWER.
thanks...
3 / (2k + 1) = 2 / (k + 2)
3k + 6 = 4k +2
k = 4. ANSWER.
thanks...
Answered by
1
Answer:
k=4
Step-by-step explanation:
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