Question

For what value of K will a+9, 2k-1and 2k+7 are consecutive terms of an AP​

Answer 1

ANSWER:

K=9+(a÷2)

Step-by-step explanation:

As the terms are in A.P

1st term = a+9(t1)

2nd term= 2k-1(t2)

3rd term= 2k+7(t3)

In A.P t2-t1=t3-t2

= 2k-1-(a+9)=2k+7-(2k-1)

= 2k-1-a-9=2k+7-2k+1

= 2k-a-10=8

= 2k= 18+a

k=(18+a)÷2

k=9+(a÷2)

Therefore if k has the value 9+(a÷2) then the terms are in consecutive A.P.

Answer 2

Step-by-step explanation:

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