For what value of k will be concecutive terms 2k+1,3k+3 and 5k-1 from an ap
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We know that, in an AP the difference is same.
so,
(3k + 3) - ( 2k +1 ) = ( 5k - 1 ) - ( 3k + 3)
➡ 3k + 3 - 2k - 1 = 5k - 1 - 3k - 3
➡ k + 2 = 2k - 4
➡ 2k - k = 2 + 4
➡ k = 6
Hope it will help you !!
so,
(3k + 3) - ( 2k +1 ) = ( 5k - 1 ) - ( 3k + 3)
➡ 3k + 3 - 2k - 1 = 5k - 1 - 3k - 3
➡ k + 2 = 2k - 4
➡ 2k - k = 2 + 4
➡ k = 6
Hope it will help you !!
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