Question

For what value of k will be consecutive terms 2k+1 , 3k+3 and 5k-1 form an ap

Answer 1

Answer: k = 6

Step-by-step explanation:

Since the terms are in ap, common difference is the same.

Therefore,

(3k+3)-(2k+1) = (5k-1)-(3k+3) (because d is the difference of consecutive terms of ap)

= 3k+3-2k-1 = 5k-1-3k-3

= k+2 = 2k-4

= 2k-k = 2+4

= k = 6