For what value of k will be k+9,2k-1 and 2k+7 are the consecutive terms of an AP?
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For the given terms to be consecutive ,
(2K-1)-(K+9) = (2K+7)-(2K-1)
2K-1-K-9 = 2K+7-2K+1
K-10 = 8
K = 18
So the required value of K is 18.
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