Math, asked by sahana21, 1 year ago

For what value of k will be k+9,2k-1 and 2k+7 are the consecutive terms of an AP?

Answers

Answered by ssm44442001
20

For the given terms to be consecutive ,

(2K-1)-(K+9) = (2K+7)-(2K-1)

2K-1-K-9 = 2K+7-2K+1

K-10 = 8

K = 18

So the required value of K is 18.


Hope this helps you.

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