Question

For what value of k will be the consecutive seems of 2k+1 ,3k+3and 5k-1 form an ap

Answer 1

[ (2k+1) + (5k-1) ] / 2 = 3k + 3
[ 2k + 1 + 5k - 1 ] = 2 ( 3k + 3 )
7k = 6k + 6
k = 6

Answer 2

(2k+1)+(5k-1)= (3k+3)
=> 2k+1+5k-1 = 3k+3
=> 7k-3k=3
=> 4k=3
=> k=3/4