Question

for what value of k will be the consecutive term 2k+1,3k+3,and 5k-1form an ap​

Answer 1

Answer:

K=6

Step-by-step explanation:

Let us assume that the terms are in AP.

Therefore,

AP : 2k+1 , 3k+3 , 5k-1 , .........

Now, in an AP we now that the common difference between any two consecutive terms is same.

so this also implies here.

So,

$a_{2} - a_{1} = a_{3} - a_{2}$

$(3k + 3) - (2k + 1) = (5k - 1) - (3k + 3)$

$3k + 3 - 2k - 1 = 5k - 1 - 3k - 3$

$k + 2 = 2k - 4$

$k - 2k = - 4 - 2$

$- k = - 6$

$k = 6$

Therefore the required value of K is 6.

Hope this helps u

plz don't forget to mark it as brainliest

Thank you

Regards

NaVila11

#followpls#

❤❤❤❤❤