For what value of k will k+2,4k-6 and 3k-2 are the consecutive terms of an AP
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here is your answer hope it helps you plz Mark as brainliest!!!
by formula in 2@. a+c=2b
by formula in 2@. a+c=2b
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Anonymous:
thanks for marking my answer as brainliest
Answered by
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for this to happen k=3
verification
k+2=3+2=5
4k-6=4(3)-6=12-6=6
3k-2=3(3)-2 =9-2 =7
5,6,7 are consecutive therefore k= 3
verification
k+2=3+2=5
4k-6=4(3)-6=12-6=6
3k-2=3(3)-2 =9-2 =7
5,6,7 are consecutive therefore k= 3
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